`int(x^3+2)/((x-1)(x-2)^2) dx`

int(x^(3)+2)/((x-1)(x-2)^(3))dx=

(1) int(2x+3)/((x-1)(x-2))dx

(1) int(2x+3)/((x-1)(x-2))dx

int(2x^(3))/((x+1)(x-3)^(2))dx

int(3x+1)/((x+2)(x-2)^(2))dx

What is int(2x^2+3)/((x^2-1)(x^2+4))dx?

int(3x+2)/((x-1)(2x+3))dx

It int (3x-2)/((x-1)(x+2)(x-2))dx=A log |x-1|B log |x+2|+C log |x-3|+C then the ascending order of A,B,C is

int(x^(2)+3x-1)/((x+1)^(2))dx

int(2x^2+3)sqrt(x+2)\ dx (ii) int(x^2+3x+1)/((x+1)^2)\ dx