[" 52.If "A=[[cos alpha,-sin alpha,0],[sin alpha,cos alpha,0],[0,0,1]]" then "(AdjA)^(-1)=],[1)I," 2) "Aquad 3)-Aquad " 4) "0]

If A=[(cos alpha, - sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)] then (AdjA)^(T)=

If A=[(cos alpha, -sin alpha, 0),(sin alpha, cos alpha,0),(0,0,1)] then A^(-1) is

Let A_(alpha)=[[cos alpha,-sin alpha,osin alpha,cos alpha,00,0,1]]

If A=([cos alpha,-sin alpha,0sin alpha,cos alpha,00,0,1]), find adj.AA(adj.A)=(adj.A)A,=|A|I_(3)

If F(alpha)=|(cos alpha, -sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)| then det F(alpha)=

Find inverse of the matrix A=[[cos alpha, -sin alpha, 0 ],[ sin alpha, cos alpha, 0],[ 0, 0, 1]]

If F(alpha)=[[cos alpha,-sin alpha, 0],[sin alpha, cos alpha, 0],[0,0,1]] , then show that F(alpha) F (beta)= F(alpha + beta) .

If A=[(cos alpha,sin alpha),(-sin alpha,cos alpha)] and A. adj A=[(k,0),(0,k)] , then k is equal to

If A=[(cos alpha,sin alpha),(-sin alpha,cos alpha)] and A. adj A=[(k,0),(0,k)] , then k is equal to