In a GP `a_1=3,a_n=96` and `S_n=189` .Find the number of terms

In a GP {a_n} , if a_1=3,a_n=96 and S_n=189 . Find common ration and n.

A G.P. has first term a=3 , last term l=96 and sum of n terms S=189 . Find the number of terms in it.

In a G.P if the first term is 3, n^(th) term is 96 and the sum of n terms is 189, then the number of terms is

In a G.P if the first term is 3, nth term is 96 and the sum of n terms is 189, then the number of terms is

The sum of terms of a G.P if a_(1)=3,a_(n)=96 and S_(n)=189 is

Show that a_1,a_2,...,a_n,... form an AP where a_n is defined as below : (i) a_n=3+4n (ii) a_n=9-5n . Also find the sum of the first 15 terms in each case.

Determine the number of terms in G.P. if a_1=3,a_n=96 and S_n=189 .

Determine the number of terms in a G.P.if a_(1)=3,a_(n)=96, and S_(n)=189.

Let the sequence a_n be defined as a_1=1, a_n=a_(n-1)+2 for n ge 2 . Find first five terms and write corresponding series.