A spring is compressed between two toy carts to masses `m_1` and `m_2`. When the toy carts are released, the spring exerts on each toy cart equal and opposite forces for the same small time t. If the coefficients of friction `mu` between the ground and the toy carts are equal, then the magnitude of displacements of the toy carts are in the ratio

Options

A. `(s_(1))/(s_(2)) = - (m_(2))/(m_(1))`
B. `(s_(1))/(s_(2)) = - (m_(1))/(m_(2))`
C. `(s_(1))/(s_(2)) = - ((m_(2))/(m_(1)))^(2)`
D. `(s_(1))/(s_(2)) = - ((m_(1))/(m_(2)))^(2)`

Answer

C