A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by :
`U_((x)) = 20 + (x - 2)^(2)`
where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J
The position of equilibrium and its nature is:

Options

A. `x = 2`, unstable
B. x = 2, stable
C. x = 2, neutral
D. no equilibrium position exists

Answer

B