The normal body-temperature of a person is `97(@)F` . Calculate the rate at which heat is flowing out of this body through the clothes asssuming the following values. Room temperature `=47^(@)F` , surface of the body under clothes `=1.6m^(-2)` , condutivity of the cloth `=0.04Js^(-1)m^(-1)`^(@)C^(-1)` , thickness of the cloth `=0.5cm.

The normal body-temperature of a person is 97^(@)F . Calculate the rate at which heat is flowing out of his body through the clothes assuming the following values. Room temperature =47^(@)F , surface of the body under clothes =1.6m^(2) , conductivity of the cloth =0.04Js^(-1)m^(-1)C^(-1) , thickness of the cloth =0.5cm .

The normal body-temperature of a person is 97^(@)F . Calculate the rate at which heat is flowing out of his body through the clothes assuming the following values. Room temperature =47^(@)F , surface of the body under clothes =1.6m^(2) , conductivity of the cloth =0.04Js^(-1)m^(-1)C^(-1) , thickness of the cloth =0.5cm .

Calculate the force acting on a body which changes the momentum of the body at the rate of 1kg - m //s^2

(a) Calculate the rate at which body heat is conducted through the clothing of a skier in a steady-state process, given the following data : the body surface area is 1.8m^(2) , and the clothing is 1.0 cm thick , the skin surface temperature is 33^(@)C and the outer surface of the clothing is at 1.0^(@)C , the thermal conductivity of the clothing is 0.040 W//m . K. (b) If , after a fall, the skier's clothes became soaked with water of thermal conductivity 0.60 W//m.K , by how much is the rate of conduction multiplied ?

Steam at 120^(@)C is continuously passed through a 50-cm long rubber tube of inner and outer radii 1.0cm and 1.2cm . The room temperature is 30^(@)C . Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = 0.15Js^(-1)m^(-1)C^(-1) .

Steam at 120^(@)C is continuously passed through a 50-cm long rubber tube of inner and outer ratii 1.0cm and 1.2cm . The room temperature is 30^(@)C . Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = 0.15Js^(-1)m^(-1) (@)C^(-1) .

Steam at 120^(@)C is continuously passed through a 50-cm long rubber tube of inner and outer radii 1.0cm and 1.2cm . The room temperature is 30^(@)C . Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = 0.15Js^(-1)m^(-1)C^(-1) .

A pitcher with 1-mm thick porous walls contain 10kg of water. ,Water comes to its outer surface and evaporates at the rate of 0.1gs^(-1) . The surface area of the pitcher (one side) =200cm^(2) . The room temperature =42^(@)C , latent heat of vaporization =2.27xx10^(6)Jkg^(-1) , and the thermal conductivity of the porous walls =0.80js^(-1)m^(-1) ^(@)C^(-1) . Calculate the temperature of water in the pitcher when it attains a constant value.

The normal body temperature is 98.6°F. When Savitri was ill her temperature rose to 103.1°F. How many degrees above normal was that?