In a Young's double-slit experiment using identical slits, when one slit is used, the total energy reaching the screen is `E_(0)` and the intensity of light at any point on the screen is `I_(0)`. When both slits are usedm and fringes are formed on the screen, the total energy reaching the screen is E and the maximum intensity on the screen is I. Then,

Options

A. `E = 2E_(0), I = 2I_(0)`
B. `E= 4E_(0), I = 4I_(0)`
C. `E = 2E_(0), I = 4I_(0)`
D. `E = 4E_(0), I = 2I_(0)`

Answer

C