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A block of mass m is placed on a horizon...

A block of mass m is placed on a horizontal surface. The coefficient of frication between them is `mu`. The block has to be moved by applying a single external force on it. The force may be applied in my direciton. The minimum value of this force must be

A

`mg`, applied vertically upward, if `mu gt 1`

B

`mumg`, applied horizontally, if `mu lt 1`

C

`(mumg)/(sqrt(mu^(2) + 1))` for all values of `mu`

D

`(mu^(2)mg)/(mu^(2) +1)` for all values of `mu`

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The correct Answer is:
C
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