A parallel- plate capacitor is charged from a cell and then isolated from it. A dielectric slab of dielectric constant K is now introduced in the region between the plated, filling half of it. The electric intensity in the diaelectric is `E_(1)` and that in air is `E_(2)`.
A
`E_(1)=E_(2)`
B
`E_(1)=(E_(2))/(K)`
C
`E_(1)=(1-(1)/(K))E_(2)`
D
`E_(1)=(E_(2))/(K-1)`
Text Solution
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The correct Answer is:
A
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