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For Zn^(2+) //Zn, E^(@) =- 0.76, for Ag...

For `Zn^(2+) //Zn, E^(@) =- 0.76`, for `Ag^(+)//Ag, E^(@) = +0.799V`. The correct statement is

A

The reactioin `rightarrow` Zn getting reduced Ag getting oxidized is spontaneous.

B

Zn undergoes reduction and Ag is oxidized.

C

Zn undergoes oxidatioin and `Ag^(+)` gets reduced.

D

No suitable answer.

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Verified by Experts

The correct Answer is:
C
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For Zn^(2+) //Zn, E^@ =- 0. 76 V , for Ag^+ //Af E^@ =0.799 V . The correct statement is .

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For a reaction Zn^(+2) + 2e^(-) rarr Zn, E^(@) = -0.76V which of the following statement is true? (E = Electrode potential)

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