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The standard oxidation potential, E^(@),...

The standard oxidation potential, `E^(@)`, for the reactions are given as:
`Zn rightarrow Zn^(2+) + 2e^(-)`, `E^(@) = +0.76V`
`Fe rightarrow Fe^(2+) + 2e^(-)`, `E^(@) = +0.41V`
The emf for the cell : `Fe^(2+) + Zn rightarrow Zn^(2+) + Fe`

A

`-0.35V`

B

`+0.35V`

C

`+1.17V`

D

`-1.17V`

Text Solution

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The correct Answer is:
B
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The standard oxidation potentials, , for the half reactions are as follows : Zn rightarrow Zn^(2+) + 2e^(-) , E^(@) = +0.76V Fe rightarrow Fe^(2+)+ 2e^(-), E^(@) = + 0.41 V The EMF for the cell reaction, Fe^(2+) + Zn rightarrow Zn^(2+) + Fe

The standard reduction potential E^(@) for the half reactions are as : E^(@) Znrightarrow Zn^2+),E^(@) = +0.76V Fe rightarrow Fe^(2+)+ 2e^(-), E^(@) = 0.41V , The emf for the cell reaction, Fe^(2+)+ZnrightarrowZn^(2+) + Fe is ,

The standard oxidation potentials, E^(@) , for the half reactions are as, Zn rarr Zn^(2+) + 2e^(-), " " E^(@) = + 0.76 volt Fe rarr Fe^(2+) + 2e^(-), " " E^(@) = +0.41 volt The emf of the cell, Fe^(2+) + Zn rarr Zn^(2+) + Fe is:

The half reactions for a cell are Zn to Zn^(2+) + 2e^(-), E^(@) = 0.76 V Fe to Fe^(2+) + 2e^(-), E^(@) = 0.41 V The DeltaG^(@) (in kJ) for the overall reaction Fe^(2+) + Zn to Zn^(2+) + Fe is

The standard reduction potential E^(@) , for the half reaction are : {:(Zn rarr Zn^(2+) + 2e^(-),,,E^(@) = 0.76 V),(Cu rarr Cu^(2+) + 2e^(-),,,E^(@) = 0.34 V):} The emf for the cell reaction, Zn(s)+Cu^(2+) rarr Zn^(2+) + Cu(s) is :

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

The standard reductino potentials E^(c-) for the half reactinos are as follows : ZnrarrZn^(2+)+2e^(-)" "E^(c-)=+0.76V FerarrFe^(2+)+2e^(-) " "E^(c-)=0.41V The EMF for the cell reaction Fe^(2+)+Znrarr Zn^(2+)+Fe is

The standard oxidation potential E^(@) for the half cell reactions are Zn rarrZn^(2+)+2e^(-):E^(@)=+0.76V FerarrFe^(2+)+2e^(-)"E^(@)=+0.41V EMF of the cell reaction Fe^(2+)+ZnrarrZn^(2+)+Fe will be

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