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According to the half-reaction table, ...

According to the half-reaction table,
`Sn^(2+) + 2e^(-) rightarrow Sn` `E_(@) = -0.14V`
`Mn^(2+) + 2e^(-) rightarrow Mn` `E^(@) = -1.03V`
Which species in the better oxidizing agent?

A

`Mn^(2+)`

B

`Sn^(2+)`

C

Mn

D

Sn

Text Solution

Verified by Experts

The correct Answer is:
B
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