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DeltaG = DeltaH - TDeltaS and DeltaG + T...

`DeltaG = DeltaH - TDeltaS` and `DeltaG + T[(d(DeltaG))/(dT)]_(p)` then `((dE_(cell)/(dT))` is:

A

`(DeltaS)/(nF)`

B

`(nF)/(DeltaS)`

C

`-nFE_(cell)`

D

`+nEF_(cell)`

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The correct Answer is:
A
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GRB PUBLICATION-ELECTROCHEMISTY-Thermodynamics in Electrochemistry
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