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Ag^(aq) + e^(-) rightarrow Ag(s) E69@) =...

`Ag^(aq) + e^(-) rightarrow Ag(s)` `E69@) = 0.80 V`
`Mg^(2+)(aq) + 2e^(-) rightarrow Mg(s)` `E^(@) = -2.73 V`
Use the equations above to calcualte the value or `DeltaG^(@0` (in kJ/mol) for the reaction:
`Mg(s) + 2Ag^(+)(aq) rightarrow Mg^(2+)(aq) + 2Ag(s)`

A

681

B

341

C

`-341`

D

`-681`

Text Solution

Verified by Experts

The correct Answer is:
D
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