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A resistance of 50Omega is registered wh...

A resistance of `50Omega` is registered when two electrodes are suspended into a beaker containing a dilute solution of a strong electrolyte such that exactly half of them are submerged into solution as shown in figure. If the solution is diluted by adding pure water (negligible conductivity) so as to just completely submerge the electrodes, the new ressitance offered by the solution would be: ltbegt

A

`50 Omega`

B

`100 Omega`

C

`25Omega`

D

`200Omega`

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A resistane of 50Omega is registered when two electrodes are suspended into beaker containing a dilute solution of a strong electrolyte such that exactly half of the them are submerged into solution. If the solution is diluted by addig pure water (negligible conductivity) so as to just completely submerge the electrodes. the new resistance offered by te solutio would be . (A). 50Omega (B). 100Omega (C). 25Omega (D). 200Omega

1.0 N solution of a salt surrounding two platinum electrodes 2.1 cm apart and 4.2 sq cm in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductivity of the solution.

In a conductivity ecll the two patinum electrodes, each of area 10 sq . Cm si fixed 1.5 cm apart . The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 Omega , find equivalent conductance of the salt solution .

In a conductivity cell the two platinum electrodes each of area 10 sq. cm are fixed 1.5 cm apart. The cell. Contained 0.05N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 ohms, find equivalent conductance of the salt solution.

The resistance of a 0.5 M solution of an electrolyte was found to be 30 Omega enclosed between two platinum electrodes. Calculate the molar conductivity of the solution if the electrodes in the cell are 1.5 cm apart and having an area of cross section 2.0 cm^(2) ?

The resistance of 0.5M solution of an electrolyte in a cell was found to be 50 Omega . If the electrodes in the cell are 2.2 cm apart and have an area of 4.4 cm^(2) then the molar conductivity (in S m^(2) mol^(-1)) of the solution is

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