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A conducting cel is filled with 0.1 M Na...

A conducting cel is filled with 0.1 M NaCl solution. Its resistance is found to be 100 `Omega` whereas its conductivity is `10^(-4) Scm^(-1)`. When the same cell is filled with `0.01 M KCl`. Solution, the resistance is found to be `50 Omega`. Calculate molar conductance of 0.01 M KCl solution.

A

`2 Scm^(2)//""mole""`

B

`20 Scm^(2)//""mole""`

C

`200Scm^(2)//""mole""`

D

`100 Scm^(2)//""mole""`

Text Solution

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The correct Answer is:
B
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Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02 M KCl solutions 520 Omega and the conductivity of 0.1 KCl solution is 1.29 S m , calculate the conductivity and moalr conductivity of 0.02 M KCl solution. Strategy : Calculate the cell constant with the help of 0.01 M KCl solution (both R and kappa are Known). Use the cell constant to determine the conductivity of 0.02 M KCl solution and finally find its molar conductivity using the molarity

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