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[Given: E(Zn^(2+)|Zn)^(@)=-.0.76V K(f)...


[Given:
`E_(Zn^(2+)|Zn)^(@)=-.0.76V K_(f)[Cu(NH_(3))_(4)]^(+2)=4xx10^(11)`
`E_(Cu^(2+)|Cu)^(@)=0.34V`
At what conc. Of `Cu^(+2)`, emf of the cell will be zero (at 298K) at conc. Of `Zn^(+2)` is remaining same?

A

`1.03xx10^(-37)`

B

`1.03xx10^(-20)`

C

`3.78xx10^(-4)`

D

0.0068

Text Solution

Verified by Experts

The correct Answer is:
A
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Given: E_(Zn^(+2)//Zn)^(@) =- 0.76V E_(Cu^(+2)//Cu)^(@) = +0.34V K_(f)[Cu(NH_(3))_(4)]^(2+) = 4 xx 10^(11) (2.303R)/(F) = 2 xx 10^(-4) At what concentration of Cu^(+2) emf of the cell will be zero (at 298K) and concentration of Zn^(+2) is remains same:

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