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Copper reduced NO(3)^(-) into NO and NO(...

Copper reduced `NO_(3)^(-)` into NO and `NO_(2)` depending upon cone. Of `HNO_(3)` in solution. Assuming `[Cu^(2+)]=0.1M` and `P_(NO)=P_(NO_(2)=10^(-3)` atm and using given data answer the following question:
`E_(Cu^(2+)|Cu)^(@)=+0.34` volt
`E_(NO_(3)^(-)|NO)^(@)=+0.96` volt
`E_(NO_(#)^(-)|NO_(3))^(@)=+0.79` volt
at 298K `(RT)/(F)(2.303)=0.06` volt
At what `HNO_(3)` concentration thermodynamic tendency for reduction of `NO_(3)^(-)` into NO and `NO_(3)` by copper is same?

A

`10^(1//23)M`

B

`10^(0.56)M`

C

`10^(0.625)M`

D

`10^(0.12)M`

Text Solution

Verified by Experts

The correct Answer is:
C
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Copper reduced NO_(3)^(-) into NO and NO_(2) depending upon cone. Of HNO_(3) in solution. Assuming [Cu^(2+)]=0.1M and P_(NO)=P_(NO_(2)=10^(-3) atm and using given data answer the following question: E_(Cu^(2+)|Cu)^(@)=+0.34 volt E_(NO_(3)^(-)|NO)^(@)=+0.96 volt E_(NO_(#)^(-)|NO_(3))^(@)=+0.79 volt at 298K (RT)/(F)(2.303)=0.06 volt E_("cell") for reduction of NO_(3)^(-)rarrNO by Cu(s), when [HNO_(3)]=1M is: [At T=298]

Copper reduced NO_(3)^(-) into NO and NO_(2) depending upon conc.of HNO_(3) in solution. Assuming [Cu^(2+)] = 0.1M , and P_(NO) = P_(NO_(2)) = 10^(-3) atm and using data answer the following questions: E_(Cu^(2+)//Cu)^(@) =+ 0.34 volt, at 298K (RT)/(F) (2.303) = 0.06 volt E_(cell) for reduction of NO_(3)^(-) rarr NO by Cu(s) when [HNO_(3)] = 1M is [At t = 298]

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