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Rh^(03+)(aq)+3e^(-)rarrRh(s) E^(@)=0.80V...

`Rh^(03+)(aq)+3e^(-)rarrRh(s) E^(@)=0.80V`
`Cu^(+)(aq)+e^(-)rarrCu(s) E^(@)=0.52V`

What is the direction of electronflow in the external circuit if the concentrations of `Cu^(+)` and `Rh^(3+)` are each 1M?

A

From the Rh anode to the Cu cathode

B

From the Rh cathode to the Cu anode

C

From the Cu anode to the Rh cathode

D

From the Cu cathode to the Rh anode

Text Solution

Verified by Experts

The correct Answer is:
C
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GRB PUBLICATION-ELECTROCHEMISTY-Comprehension type
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