Home
Class 12
CHEMISTRY
If electrode potential of following cell...

If electrode potential of following cell:
`Pt_(s)|Fe_(aq)^(2+),Fe_(aq)^(3+)||MnO_(4(aq))^(-),Mn_(aq)^(2+),H_(aq)^(+)|Pt_(s)`
is X then calculate value of 20X.
[Given: `E_(MnO_(4)^(-)|Mn^(2+)` = 1.51 V,`
`E_(Fe^(3+)|Fe^(2+))^(@)` = 0.78 V, (2.303 RT)/F = 0.06]`

Text Solution

Verified by Experts

The correct Answer is:
5
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTY

    GRB PUBLICATION|Exercise Match the column type|16 Videos
  • D-BLOCK ELEMENTS

    GRB PUBLICATION|Exercise Subjective Type|18 Videos
  • ENVIRONMENTAL CHEMISTRY

    GRB PUBLICATION|Exercise Straight objective type|40 Videos

Similar Questions

Explore conceptually related problems

Write cell reaction of the following cells: (a). Pt|Fe^(2+),Fe^(3+)||MnO_(4)^(-),Mn^(2+),H^(+)|Pt (b). Pt,Cl_(2)|Cl^(-)(aq)||Ag^(+)(aq)|Ag

Determine the potential of the following cell: Pt|H_2(g,0.1 "bar")|H^+(aq,10^(-3)M"||"MnO_4^-)(aq),0.1M) Mn^(2+)(aq,0.01M),H^+(aq,0.01M)|Pt Given : E_(MnO_4^(-)|Mn^(2+))^(@)=1.51V

For the following electrochemical cell at 298 k Pt_(s) H_(g)(1bar)| H^(+)_(1M)||M _(aq)^(4+) , +(aq)^(2+) |Pt_(s)E _(cell) = 0.092V When ([M_(aq)^(2+)])/([M_(aq)^(4+)] )=10^(X) . Given : E_(M^(4+)//M^(2+))^(@) = 0.151 V , 2.303(RT)/(F) = 0.059V ] The value of X is ,

Complete the following a. Fe_((s))+H_(2)O_((g))to b. PbS_((s))+H_(2)O_(2(aq))to c. MnO_(4(aq))^(ɵ)+H_(2)O_(2(aq))to

For the following electrochemical cell at 298K Pt(s)+H_(2)(g,1"bar") |H^(+) (aq,1M)||M^(4+)(aq),M^(2+)(aq)|Pt(s) E_(cell) = 0.092 V when ([M^(2+)(aq)])/([M^(4+)(aq)])=10^(x) Given, E_(M^(4+)//M^(2+))^(@) = 0.151V, 2.303 (RT)/(F) = 0.059 The value of x is-

For the balanced equation : 8H^(+)(aq)+5Fe^(2+)(aq)+MnO_(4)^(-)(aq)rarr5Fe^(3+)(aq)+Mn^(2+)(aq)+4H_(2)O(l) Which statement is correct ?

GRB PUBLICATION-ELECTROCHEMISTY-Subjective type
  1. During electrolytes 40 mA current is passed through 100 mL of 0.2 M Fe...

    Text Solution

    |

  2. 4.0 L of a buffer solution is prepared that is 1.0 M NaH(2)PO(4) and 1...

    Text Solution

    |

  3. For the cell: Pt|Hg(l)|Hg(2)Cl(2)(s)|KCl(1 M)||H^(+)|Q|H(2)Q|Pt E(c...

    Text Solution

    |

  4. Find the EMF of cell (in volts) formed by connected two half cells: ...

    Text Solution

    |

  5. Calcualte acid dissociatioin constant for 0.1 M HCOOH if its solution ...

    Text Solution

    |

  6. H(2)O(2) would have as oxidant with respect to how many of the followi...

    Text Solution

    |

  7. For the cell reaction: Hg(2)Cl(2)(s) + 2Ag(s) rightarrow 2Hg(l) + 2A...

    Text Solution

    |

  8. The possibility of plutonium waste leaking from nuclear faciliteis is ...

    Text Solution

    |

  9. The conductivity of saturated solution of sparinlgy soluble salt Ba(3)...

    Text Solution

    |

  10. If electrode potential of following cell: Pt(s)|Fe(aq)^(2+),Fe(aq)^(...

    Text Solution

    |

  11. 100 mL of 1M AgNO(3) solution is electrolysed using Pt electrode by pa...

    Text Solution

    |

  12. The emf of a cell formed by dipping two electrons of metal (M) in two ...

    Text Solution

    |

  13. Resistance of an aqueous solution containing 2 "mole" NH(4)Cl and is f...

    Text Solution

    |

  14. The reduction potential of hydrogen electrode at 25^(@)C when placed i...

    Text Solution

    |

  15. E(cell)^(@) for the cell: Pt(s) | Fe^(2+)(aq)|Fe^(3+)(aq)||MnO(4)^(-...

    Text Solution

    |

  16. A cell reaction is represented as Pt|H(2)Q,Q,H^(+)||KCl|AgCl|Ag. E...

    Text Solution

    |

  17. 0.5 L of a saturated solution of Ag(2)CrO(4) is mixed with 0.5 L of 2 ...

    Text Solution

    |

  18. A saturated solution of sparingly soluble base Fe(OH)(3) is found to h...

    Text Solution

    |

  19. Two chambers in a galvanic cell have volume equal to 1 litre. If one c...

    Text Solution

    |

  20. A current of 0.5 amp is passed through excess of molten mixture of Al(...

    Text Solution

    |