A saturated solution of sparingly soluble base `Fe(OH)_(3)` is found to have a specific conductance of `50 xx 10^(-4)ohm^(-1)m^(-1)`. Calcualte the value of a four digit number abcd where,
`ab = 3xx10^(16)` times solubility product of `Fe(OH)_(3)`
cd =` 6 xx 10^(4)` times solubility `Fe(OH_(3)` in a solution of pH = 10
[Given : `lambda_(eq)^(infty)FeCl_(3) = 15 xx 10^(-3)Sm^(2)eq^(-1)`
`lambda_(eq)^(infty)NaCl = 13 xx 10^(-3)Sm^(2)eq^(-1)`
`lambda_(eq)^(infty)NaOH = 23 xx 10^(-3)Sm^(2)eq^(-1)`

Answer

1632