one gram of activated carbon has a surface are of `1000m^(2)`. Considering complete coverage as well as monomolecular adsorption , how much ammonia at 1 atm and 273 K would be absorbed on the surface of `44/7` g carbon if radius of a ammonia molecules is `10^(-8) cm`.
The volume of nitrogen gas Um (measured at STP) required to cover a sample of silica get with a mono-molecular layer is 129 cm^(3) g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.2 xx 10^(-20) m^(2).
The volume of nitrogen gas Vm (at STP) reqired to cover a sample of silica gel with a monomolecular layer is 129cm^(3)g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.23xx10^(-20)m^(2) .
Finely divided catalyst has greater surface area and has greater catalytic activity than the compact solid. If a total surface area of 6291456 cm^(2) is required for adsorption in a catalytic gaseous reaction, then how many splits should be made in a cube of exactly 1 cm in length to achieve required surface area? [Given : One split of a cube gives eight cubes of same size]
A solution of palmitic acid (M=256) in benzene contains 4.24 g acid per litre. When this solution is dropped on the water surface, benzene evaporates and palmitic acid forms monomolecular film of the solid type. If we wish to cover an area of 500 cm^(2) with a monolayer, what volume of solution should be used ? The area occupied by one palmitic acid molecule may be taken to be 21 xx 10^(-20) m^(2)
1 L of 0.6 M acetic acid is shaken with 2 g activated carbon.Activated carbon absorbs some acetic acid on its surface only.This process is called adsorption.The final concentration of the solution after adsorption is 0.5 M.What is the amount of acetic acid absorbed per gram of carbon.
NARENDRA AWASTHI-SURFACE CHEMISTRY-Level 3 - Assertion - Reason Type Questions
