Home
Class 12
CHEMISTRY
The rate of a reaction is expressed in d...

The rate of a reaction is expressed in different ways as follows:
`+(1)/(2)(d[C])/(dt)=-(1)/(3)(d[D])/(dt)=+(1)/(4)(d[A])/(dt)=-(d[B])/(dt)`
the reaction is

A

`4A+Bto2C+3D`

B

`B+3Dto4A+2C`

C

`A+BtoC+D`

D

`B+DtoC+D`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the reaction based on the given rate expressions, we will analyze the stoichiometric coefficients and the relationship between the reactants and products. ### Step-by-Step Solution: 1. **Identify the Rate Expressions**: The rate of the reaction is given as: \[ +\frac{1}{2}\frac{d[C]}{dt} = -\frac{1}{3}\frac{d[D]}{dt} = +\frac{1}{4}\frac{d[A]}{dt} = -\frac{d[B]}{dt} \] 2. **Assign Stoichiometric Coefficients**: From the rate expressions, we can assign stoichiometric coefficients to each species: - For \(C\), the coefficient is \(2\) (since it is multiplied by \(\frac{1}{2}\)). - For \(D\), the coefficient is \(3\) (since it is multiplied by \(-\frac{1}{3}\)). - For \(A\), the coefficient is \(4\) (since it is multiplied by \(\frac{1}{4}\)). - For \(B\), the coefficient is \(1\) (since it is multiplied by \(-1\)). 3. **Write the Balanced Reaction**: Based on the stoichiometric coefficients, we can write the balanced chemical equation: \[ B + 3D \rightarrow 4A + 2C \] 4. **Final Reaction**: The final reaction can be summarized as: \[ B + 3D \rightarrow 4A + 2C \] ### Conclusion: The reaction represented by the given rate expressions is: \[ B + 3D \rightarrow 4A + 2C \]
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos

  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

The rate of a reaction is expressed in different ways as follows +1/2 (d[C ])/(dt)=-(1)/(5) -(d[D])/( dt)=+(1)/(3 ) [d[A ])/(dt) =-(d[B])/(dt) the reaction is ________.

The rate of the reaction may be expressed by the following different ways . (1)/(2) (d[A])/(dt)=-(1)/(3)(d[B])/(dt)=(-d[C])/(dt) reaction is

d/(dt) (1/t)=

The rate of reaction of certain reaction is expressed as : (1)/(3)(d[A])/(dt)=-(1)/(2)(d[B])/(dt)=-(d[C])/(dt) The reaction is :

The rate and mechamical reaction are studied in chemical kinetics. The elementary reactions are single step reaction having no mechanism. The order of reaction and molecularity are same for elementary reactions. The rate of forward reaction aA + bBrarr cC+dD is given as: rate =((dx)/(dt))=-1/a(d[A])/(dt)=-1/b(d[B])/(dt)=1/c(d[C])/(dt)=1/d(d[D])/(dt) or expression can be written as : rate =K_(1)[A]^(a)[B]^(b)-K_(2)[C]^(c )[D]^(d) . At equilibrium, rate = 0 . The constants K, K_(1), K_(2) are rate constants of respective reaction. In case of reactions governed by two or more steps reaction mechanism, the rate is given by the slowest step of mechanism. For a gaseous reaction, the rate is expressed in terms of (dP)/(dt) in place of (dC)/(dt) or (dn)/(dt) where C is concentration, n is number of moles and 'P' is pressure of reactant. The three are related as: