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Decomposition of NH(4)NO(2)(aq into N(2)...

Decomposition of `NH_(4)NO_(2)(aq` into `N_(2)(g)` and `2H_(2)O(l)` is first order reaction.

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To solve the problem regarding the decomposition of ammonium nitrite (NH₄NO₂) into nitrogen gas (N₂) and water (H₂O), we need to analyze the reaction and its characteristics as a first-order reaction. Here’s a step-by-step solution: ### Step 1: Write the Reaction The decomposition reaction can be represented as: \[ \text{NH}_4\text{NO}_2(aq) \rightarrow \text{N}_2(g) + 2\text{H}_2\text{O}(l) \] ### Step 2: Identify the Order of the Reaction The problem states that this is a first-order reaction. In a first-order reaction, the rate of reaction is directly proportional to the concentration of one reactant. ### Step 3: Write the Rate Law For a first-order reaction, the rate law can be expressed as: \[ \text{Rate} = -\frac{d[\text{NH}_4\text{NO}_2]}{dt} = k[\text{NH}_4\text{NO}_2] \] where \( k \) is the rate constant. ### Step 4: Integrate the Rate Law To find the relationship between concentration and time, we need to integrate the rate law. Rearranging gives: \[ \frac{d[\text{NH}_4\text{NO}_2]}{[\text{NH}_4\text{NO}_2]} = -k dt \] Integrating both sides: \[ \int \frac{d[\text{NH}_4\text{NO}_2]}{[\text{NH}_4\text{NO}_2]} = -k \int dt \] This results in: \[ \ln[\text{NH}_4\text{NO}_2] = -kt + C \] Where \( C \) is the integration constant. At \( t = 0 \), let \( [\text{NH}_4\text{NO}_2] = [\text{NH}_4\text{NO}_2]_0 \): \[ \ln[\text{NH}_4\text{NO}_2]_0 = C \] Substituting back gives: \[ \ln[\text{NH}_4\text{NO}_2] = -kt + \ln[\text{NH}_4\text{NO}_2]_0 \] ### Step 5: Exponential Form Exponentiating both sides to eliminate the natural logarithm yields: \[ [\text{NH}_4\text{NO}_2] = [\text{NH}_4\text{NO}_2]_0 e^{-kt} \] ### Step 6: Graphical Representation The concentration of NH₄NO₂ decreases exponentially over time. The graph of concentration vs. time for a first-order reaction will show a downward curve, indicating that as time increases, the concentration of NH₄NO₂ decreases. ### Step 7: Identify the Correct Graph Based on the characteristics of a first-order reaction, the graph will be an exponential decay curve. Among the options provided, the correct graph will be the one that shows a decreasing exponential trend. ### Conclusion The correct answer is the graph that represents an exponential decrease in concentration over time. ---
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