Home
Class 12
CHEMISTRY
Complete the following nuclear equation ...

Complete the following nuclear equation by suppling the symbol for the other product of the fission :
`._(92)^(235)U+_(0)^(1)n rarr _(38)^(94)Sr +………+2_(0)^(1)n`

A

`._(54)^(139)Xe`

B

`._(54)^(140)Xe`

C

`._(64)^(104)Gd`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos
  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos
  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

Complete the equation for the following fission process : ""_(92)U^(235)+""_(0)n^(1)to""_(38)Sr^(0)+ …..

Fill in the blank ""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n

Knowledge Check

  • The product p of the nuclear reaction ._(92)^(235)U + ._(0)^(1) n rarr p + ._(36)^(92)Kr + 3 ._(0)^(1)n is

    A
    `._(56)^(141)Sr`
    B
    `._(56)^(141)La`
    C
    `._(56)^(141)Ba`
    D
    `._(56)^(141)Cs`
  • The product p of the nuclear reaction ""_(92)^(235)U + ""_(0)^(1)n to p + ""_(36)^(92)Kr + 3 ""_(0)^(1)n is

    A
    `""_(56)^(141)Sr`
    B
    `""_(56)^(141)La`
    C
    `""_(56)^(141)Ba`
    D
    `""_(56)^(141)Cs`
  • The missing particle in the reaction, ._(92)^(235)U + ._(0)^(1)n rarr ._(56)Ba^(146) + ...+ 3_(0)^(1) n is

    A
    `._(32)^(87)Ge`
    B
    `._(35)^(89)Br`
    C
    `._(36)^(87)Kr`
    D
    `._(23)^(86)Br`
  • Similar Questions

    Explore conceptually related problems

    Complete the equation for the following fission process : ""_(92)^(235) U + _(0)^(1) n to _(38)^(90) Sr + . . .

    Equation ._(17)Cl^(37) + ._(1)H^(2) rarr ._(18)Ar^(38) + ._(0)n^(1) is

    Identify the missingf product in the given reaction ""_(92)""^(235)Uto""_(0)""^(1)nto?+""_(36)""^(92)Kr+3""_(0)""^(1)n

    The reaction ._(92)U^(235) + ._(0)n^(1) rarr ._(56)Ba^(140) + ._(36)Kr^(93) + 3 ._(0)n^(1) represents

    Complete the equation for the following fission process ._92 U^235 ._0 n^1 rarr ._38 Sr^90 +.... .