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.(92)^(235)U+(0)^(1)n rarr (56)^(139)Ba ...

`._(92)^(235)U+_(0)^(1)n rarr _(56)^(139)Ba +_(36)^(94)Kr +3_(0)^(1)n+200MeV`
Total energy released (in MeV) after `5^(th)` stage of fission is:

A

48600

B

16200

C

24200

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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In the nuclear chain ractio: ._(92)^(235)U + ._(0)^(1)n rarr ._(56)^(141) Ba + ._(36)^(92)Kr + 3 ._(0)^(1)n + E The number fo neutrons and energy relaesed in nth step is:

The reaction ._(92)U^(235) + ._(0)n^(1) rarr ._(56)Ba^(140) + ._(36)Kr^(93) + 3 ._(0)n^(1) represents

A nuclear reaction is represented by the following equation : ._(92)^(235)U + ._(0)^(1)n rarr ._(56)^(139)Ba + ._(36)^(94)Kr + xc + E (a) Name the process represented by this equation and describe what takes place in this reaction. (b) Identify the particle c and the number x of such particles produced in the reaction. (c ) What does E represent ? (d) Name one installation where the above nuclear reaction is utilised. (e) What type of bomb is based on similar type of reactions ?

The ._(92)U^(235) absorbs a slow neturon (thermal neutron) & undergoes a fission represented by ._(92)U^(235)+._(0)n^(1)rarr._(92)U^(236)rarr._(56)Ba^(141)+_(36)Kr^(92)+3_(0)n^(1)+E . Calculate: The energy released when 1 g of ._(92)U^(235) undergoes complete fission in N if m=[N] then find (m-2)/(5) . [N] greatest integer Given ._(92)U^(235)=235.1175"amu (atom)" , ._(56)Ba^(141)=140.9577 "amu (atom)" , ._(36)r^(92)=91.9263 "amu(atom)" , ._(0)n^(1)=1.00898 "amu", 1 "amu"=931 MeV//C^(2)

Which of the following is correct regarding nuclear fission? (i) The process in which a heavy nucleus is broken into two nearly equal fragments, is called ‘Nuclear Fission’ (ii) Nautral uranium has two istopes, ._(92)U^(238) and ._(92)U^(235) in the ratio 1 : 0.07 . the fission of U^(235) takes place only by fats neutrons, whereast that of U^(235) is possible by slow neutrons (iii) One of the reaction for fission of U^(235) ._(92)^(236)U+._(0)^(1)nrarr._(92)^(236)Urarr._(52)^(144)Ba+._(36)^(89)Kr+3_(0)^(1)n + energy (iv) In the fission of one U^(235) nucleus, about 200MeV of enegry of obtained. Most of this enegry is obtained from of K.E. of fragments obtained by fission, the rest of obained as K.E. of emitted neutrons, gamma -rays, heat and light radiation

""_(92)^(235)U+X to Ba +Kr +3 ""_(1)^(0)n X is

When Uranium is bombarded with neutrons , it undergoes fission . The fission reaction can be written as : ""_(92) U^(235) + ""_(0) n^(1) to ""_(56) Ba^(141) + ""_(36) Kr^(92) + 3x + Q (energy) where three particles named x are produced and energy Q is released . What is the name of the particle x ?

A slow neutron strikes a nucleus of ._(92)^(235)U splitting it into lighter nuclei of ._(56)^(141)Ba and ._(36)^(92)Kr along with three neutrons. The energy released in this reaction is ( The masses of uranium, barium and krypton of this reaction are 235.043933,140.917700 and 91.895400 u respectively. The mass of a neutron is 1.008665 u

NARENDRA AWASTHI-CHEMICAL KINETIC & NUCLEAR CHEMISTRY-Level 1 (Q.93 To Q.122)
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  2. A radioactive nuclide emitts gamma- rays due to the :

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  4. Consider the following decay .(Z)^(A)Xrarr(Z-1)^(A)Y+(+1)^(0)e,(beta^(...

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  7. ………. Is produced when a positron and an electron collide.

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  10. Emission of beta -particle is equivatent to:

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  11. Pair of isobar is :

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  12. The 'group displacement law' was given by :

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  13. .(7)^(7)Li + (1)^(1)P rarr X, Identify X if reaction is (p,alpha) type...

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  14. Identify reaction type: (13)^(27)Al+(1)^(2)H rarr (13)^(28)Al+(1)^(1...

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  16. What will be the product of reaction .(101)^(255)Md(alpha,2n)?

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  17. .(92)^(235)U+(0)^(1)n rarr (56)^(139)Ba +(36)^(94)Kr +3(0)^(1)n+200MeV...

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