Home
Class 12
CHEMISTRY
Alpha decay of .(92)^(238)U forms .(90)^...

Alpha decay of `._(92)^(238)U` forms `._(90)^(234)Th`. What kind of decay from `._(90)^(234)Th` produces `._(84)^(234)Ac` ?

A

`alpha`

B

`beta`

C

`beta^(+)`(positron)

D

`gamma` -emission

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos

  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

Part of uranium decay series is shown ._(92)U^(234) to ._(90)Th^(234) to ._(91) Pa^(234) to ._(90)Th^(230) to ._(88)Ra^(226) How many parts of isotopes are there in the above series

Calculate the amount of energy released during the alpha -decay of ._(92)^(238)Urarr_(90)^(234)Th+._(2)^(4)He Given: atomic mass of ._(92)^(238)U=238.05079 u , atomic mass of ._(90)^(234)Th=234.04363 u , atomic mass ._(2)^(4)He=4.00260u , 1u=931.5 MeV//c^(2) . Is this decay spontaneous?Give reason.

In the nuclear reaction ._(90)^(234)Th rarr ._(91)^(234)Pa + X . X is -

Uranium ._(92)^(238)U is an ustable nucleus. It decays to Thorium ._(92)^(238)Th , which is again an unstable nucleus which further decays to ._(91)^(234)Pa . Let ._(92)^(238)U be called A of decay constant lambda_(1) and ._(90)^(234)Th is called as B of decay constant lambda_(2) and stable nuclei ._(91)^(234)Pa be called as C . Here A is called parent nucleus and B is called daughter nucleus of A . Any two adjacent nuclei may be consider parent or daughter nuclei A, B and C respectively at time 't' . Then we can write Aoverset(lambda_(1))rarrBoverset(lambda_(2))rarrC Rate of disintergration of A=(dN_(1))/(dt)=lambda_(1)N_(1) Rate of disintergration of B=(dN_(2))/(dt)=lambda_(1)N_(1)-lambda_(2)N_(2) Rate of formation of nuclei C is equal to (dN_(3))/(dt)=lambda_(2)N_(2) If at t=0 , there are N_(0) number of nuclei of A where as nuclei B and C are absent in the sample Answer the following questions Number of nuclei of B at any time t is

Uranium ._(92)^(238)U is an ustable nucleus. It decays to Thorium ._(92)^(238)Th , which is again an unstable nucleus which further decays to ._(91)^(234)Pa . Let ._(92)^(238)U be called A of decay constant lambda_(1) and ._(90)^(234)Th is called as B of decay constant lambda_(2) and stable nuclei ._(91)^(234)Pa be called as C . Here A is called parent nucleus and B is called daughter nucleus of A . Any two adjacent nuclei may be consider parent or daughter nuclei A, B and C respectively at time 't' . Then we can write Aoverset(lambda_(1))rarrBoverset(lambda_(2))rarrC Rate of disintergration of A=(dN_(1))/(dt)=lambda_(1)N_(1) Rate of disintergration of B=(dN_(2))/(dt)=lambda_(1)N_(1)-lambda_(2)N_(2) Rate of formation of nuclei C is equal to (dN_(3))/(dt)=lambda_(2)N_(2) If at t=0 , there are N_(0) number of nuclei of A where as nuclei B and C are absent in the sample Answer the following questions ltbgt Numeber of the nuclei of nuclei C at time t is

Calculate the energy released in MeV in the following nuclear reaction : ._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u Mass of ._(90)^(238)Th=234.043630 u Massof ._(2)^(4)He=4.002600 u 1u = 931.5 MeV//c^(2)]