Home
Class 12
CHEMISTRY
The present activity of the hair of Egyp...

The present activity of the hair of Egyption mummy is 1.75 dpm `t_(1//2)` of `._(6)^(14)C` is 5770 year and disintegration rate of fresh smaple of `C^(14)` is 14 dpm . Find out age of mummy.

A

23080 year

B

138480 year

C

11998.3 year

D

17310 year

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos
  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos
  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

The activity of the hair of an Egyptian mummy is 7 disintegration "min"^(-1) of C^(14) . Find an Egyptian mummy. Given t_(0.5) of C^(14) is 5770 year and disintegration rate of fresh sample of C^(14) is 14 disintegration "min"^(-1) .

The activity of the hair of an egyptain mummy is 7 disinetgration "minute"^(-1) of of C^(14) . Find the age of mummy. Given t_(0.5) of C^(14) is 1570 year and disintegration rate of fresh sample of C^(14) is 14 disntegration "minute"^(-1) .

t_(1//2) of C^(14) isotope is 5770 years. time after which 72% of isotope left is:

The activity of an old piece of wood is just 1/4 of the fresh piece of wood. If t_(1//2) of C-14 is 6000 years, the age of the piece of wood is

A sample of wooden aircrafts is found to undergo 9 dp m g^(-1) of .^(14)C . What is appoximate age of aircraffts? The half line of ._(6)^(14)C is 5730 year and rate of disintergration of wood recently cut down is 15 dp m g^(-1) do ._(6)^(14)C ?

What mass fo C^(14) with t_(1//2) = 5730 year has activity equal to one curie?

What mass of C^(14) with t_(1//2) = 5730 years has activity equal to curie?