Home
Class 12
CHEMISTRY
Reaction A+BrarrC+D follows rate law .r=...

Reaction `A+BrarrC+D` follows rate law .`r=k[A]^(1//2)[B]^(1//2)` Starting with 1 M of A and B each. What is the time taken fro concetration of A become `0.1M`?
(Given`k=2.303xx10^(-2)sec^(-1))`

A

10 sec

B

100 sec

C

1000 sec

D

434 sec

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos

  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

Reaction A+B rarr C+D follows rate law R=K[A]^(1//2)[B]^(1//2) starting with 1 M of A and B . What is time taken for concentration of A to become 0.1 M ? [Given , k=4.606xx10^(-4)s^(-1) ]

Reaction A+BtoC+D is started with 1 M of each A and B and follows the rate law r=k[A]^(1//2)[B]^(1//2) What is the time taken for the concentration of A to drop to 0.1 M (K=2.303xx10^(-3)sec^(-1))

For a reaction A+B to P, the rate law is given by: r=k[A]^(1//2)[B]^(2) What is the order of the reaction?

For the following reaction A(g) + B(g) rarr 2C(g) + D(g), the law is given as R = [A]^(1//3).[B]^(2//3) . If initially concentration of A and B are unity then total molar concentration of all gases at t=600 sec. will be : [Given : K=2.31xx10^(-3)sec^(-1) ]

For a reaction, A+Brarr Product, the rate law is given by r=k[A]^((1)/(2))[B]^(2) . What is the order of the reactio ?

For a reaction, A+B to Products, the rate law is given by: r=k[A]^(1//2)[B]^(2) . What is the order of reaction:

(a) For a reaction ABrarrP , the rate law is given by, r=k[A]^(1//2)[B]^(2). What is the order of this reaction? (b) A first order reaction is found to have a rate constant k=5.5xx10^(-14)s^(-1) , Find the half life of the reaction.