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" iv "2y^(3)+y^(2)-2y-1...

" iv "2y^(3)+y^(2)-2y-1

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Factorise : - 2y^(3)+y^(2)-2y-1

If y=(sqrt(3)+1)/(2) then find the value of 4y^(3)+2y^(2)-8y+10=

Factorise : 2y^3+y^2-2y-1 .

Subtract : 5y^(4) - 3y^(3) + 2y^(2) + y - 1 from 4y^(4) - 2y^(3) - 6y^(2) - y + 5

Subtract: (-2y^(2)+(1)/(2)y-3) om 7y^(2)-2y+10

Factorise : (iv) (2x - y)^(3) - (2x - y)

If ({(y+1)^(3)+(y-1)^(3)})/(((y+1)^(2)-(y-1)^(2)))=3y then the value of y+(3)/(y) is