[055],[[3-5times10-5times125],[5^(-7)times6^(-5)]]

(3^(-5)times10^(-5)times125)/(5^(-7)times6^(-5))

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

(5)/(7)times(5)/(7)times(5)/(7)times(5)/(7)

[8^(-2/3)times2^(1/2)times25^(-5/4)]÷[32^(-2/5)times125^(-5/6)] =sqrt2

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Verify (3times7) times5=3times(7times5)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

a) (441)/(250)times(37)/(21)times(125)/(111)times(3)/(5)times-5

Solve: 5/7 times 5/7 times 5/7 times 5/7

Evaluate : ( 3^-5 times a^-6 times b^-4) /( 3^-6 times a^-5 times b^-3 )