Consider the situation shown in the figure. The wire `PQ` has mass `m` , resistance `r` and can slide on the smooth, horizontal parallel rails separated by a distance `l` . The resistance of the rail is negligible. A uniform magnetic field `B` exists in the rectangular region and a resistance `R` connects the rail outside the field region. At `t=0` , the wire `PQ` is pushed toward right with a speed `v_(0)` . Find
(a) the current in the loop at an instant when the speed of the wire `PQ` is `v`
(b) the acceleration of the wire as this instant
(c) the velocity `v` as a function of `x`
(d) the maximum distance the wire will move
(e) the velocity as a function of time

Options

A. `v = v_(0) - (2B^(2)l^(2)x)/(m(R + r))`
B. `v = v_(0) - (B^(2)l^(2)x)/(m(R + r))`
C. `v = v_(0) - (B^(2)l^(2)x)/(2m(R + r))`
D. none of these

Answer

b