[x+2y+z=7],[x+3z=11],[2x-3y=1]

Solve: x+2y+z=7x+3z=112x-3y=1

Solve by matrix method : x + 2y + z = 7, x + 3z= 11, -3y + 2x = 1.

Solve the following system of linear equations by matrix inversion method: x + 2y + z = 7,x + 3z = 11 and 2x - 3y = 1

The solutions of the equations x+2y+3z=14,3x+y+2z=11,2x+3y+z=11

Solve the following system of equations by matrix inversion method. {{:(x + 2y + z = 7 ),(" "x + 3z = 11),(" "2 x - 3y = 1 ):}

Solve 3x-y+2z=12, x+2y+3z=11, 2x-2y-z=2

The solutioni of x+y+z=7,x+2y+3z=16,x+3y+4z=22 is

x+y+z=1 x-2y+3z=2 5x-3y+z=3

The system of equations x +2y+3z=1, x-y+4z=0, 2x+y+7z=1 has