(1)(3(x-3)=5(2t+1)

If 3(t-3) = 5(2t + 1) , then t = ?

Solve the following equations : 3 (t-3) = 5 (2t - 1)

If x=7/(1+t^3), y=(7t)/(1+t^3) , then show that (dy)/(dx)=(2t^3-1)/(3t^2)

if f(x)=int_(-1)^(x)t(e^(t)-1)(t-1)(t-2)^(3)(t-3)^(5)dt has a local minimum then sum of values of x

if f(x)=int_(-1)^(x)t(e^(t)-1)(t-1)(t-2)^(3)(t-3)^(5)dt has a local minimum then sum of values of x

The function int_(-1)^(x)t(e^t-1)(t-1)(t-2)^3(t-3)^5dt has local minimum at x=

The function f(x)=int_(-1)^(x)t(e^(t)-1)(t-1)(t-2)^(3)(t-3)^(5)dt has a local minimum at x=0(b)1(c)2(d)3

Assertion (A) : (1)/(5)+(1)/(3.5^(3))+(1)/(5.5^(5))+(1)/(7.5^(7))+…(1)/(2)log((3)/(2)) Reason (R ) : If |x| lt 1 then log_(e )((1+x)/(1-x))=2(x+(x^(3))/(3)+(x^(5))/(5)+…)

If u=sin^(-1)(x-y),x=3t,y=4t^(3) , then what is the derivative of u with respect to t? (A) 3(1-t^2) (B) 3(1-t^2)^(-1/2) (C) 5(1-t^2)^(-1/2) (D) 5(1-t^2)