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SUBHASH PUBLICATION-TRIGONOMETRY-Prove the following
- sin(A+B).sin(A- B)=sin^(2)A-sin^(2)B
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- cos (A+B).cos(A-B)=cos^(2)A-sin^(2)B
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- tan((pi)/4+A)=(1+tanA)/(1-tanA)
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- tan((pi)/4-A)=(1-tanA)/(1+tanA)
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- cot(A+B)=(cotA.cotB-1)/(cotB+cotA)
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- cot(A-B)=(cotA.cotB+1)/(cotB-cotA)
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- If sinA=3//5,cosB=5//13 & A,B are acute, find sin(A+B)
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- If sinA=4/5,cosB=(-12)/13 and (pi)/2ltA,Bltpi , Find sin(A-B)
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- Prove that cos(120^(@)+A)+cos(120^(@)-A)=-cosA
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- (cos2A)/(secA)+(sin2A)/(cosecA)=cosA
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- If "tan"A=1/2,tan(A+B)=1/3 find tanB.
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- If tanA=1/2,tanB=1/3, Prove that A+B=(pi)/4
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- (sin 2 theta)/(1-cos 2 theta)=cot theta
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- (1+cos 2 theta)/(sin 2 theta)=cot theta
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- cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)
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- (1-cos2A+sin2A)/(1+cos2A+sin2A)=tanA
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- (sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)
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- (sin3A)/(sinA)-(cos3A)/(cosA)=2
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- Prove that (sin 3 theta)/(1+2cos2 theta)=sin theta and hence find sin1...
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- cos4x=1-8sin^(2)x cos^(2) x
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