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[cos36^(@)-cos72^(@)=],[[" 1) "1," 2) "(...

[cos36^(@)-cos72^(@)=],[[" 1) "1," 2) "(1)/(2)]]

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cos 36^@ - cos72^@ =

cos 36^(@) - cos 72^(@) =

cos6^(@)sin24^(@)cos72^(@)=

cos6^(@)*sin24^(@)*cos72^(@)=

Show that cos36^(@) cos72^(@) cos108^(@) cos144^(@)=(1)/(16)

Prove that: cos36^(@)cos72^(@)cos108^(@)cos144^(@)=(1)/(16)

cos^(2) 36^(@) + cos^(2) 72^(@)=

Prove that (1)cos36^(@)cos72^(@)cos108^(@)cos144^(@)=(1)/(16)(2) Show that 4sin27^(@)=sqrt(5+sqrt(5))-sqrt(3-sqrt(5))

Prove that cos36^(@)cos72^(0)cos108^(0)cos144^(0)=(1)/(16)