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[" Question 2: "],[" A particle is proje...

[" Question 2: "],[" A particle is projected up with an initial velocity of "],[80" ft/sec.The ball will be at a height of "96ft" from the "],[" ground after "]

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A ball is thrown vertically upward from the top of a building 96feet tall with an initial velocity of 80feet per second. The distance S (in feet )of the ball from the ground, after t seconds is S = 96 + 80t − 16t^(2) . After how many seconds does the ball strike the ground.

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .

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Figure shown V_(y)-t graph of a particle projected from the ground. Then its height at t=2 sec will be