[x+(y)/(2)=4],[(x)/(3)+2y=5]

Solve the following system of equations: x+(y)/(2)=4,quad (x)/(3)+2y=5

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

x"@"y=(x+y)^(2) x#y=(x-y)^(2) (2" @ "2)+(3#3)-(4"@"4)+(5#5) is equal to :

{:((1)/(2(x + 2y)) + (5)/(3(3x - 2y))=(-3)/(2)),((5)/(4(x + 2y)) - (3)/(5(3x - 2y)) = (61)/(60)):}

Solve : {:((34)/(3x+4y)+(15)/(3x-2y)=5),((25)/(3x-2y)-(8.50)/(3x+4y)=4.5):}

If log_(5)(3^(x)-4^(y))=3 and 3^((x)/(2))-2^(y)=5, then (x)/(y) is equal to