(cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

Show that :((cos theta-cos3 theta)(sin8 theta+sin2 theta))/((sin5 theta-sin theta)(cos4 theta-cos6 theta))=1

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

If (sin theta + cos theta)/(sin theta - cos theta)=3 , then the value of sin^(4)theta - cos^(4)theta is:

Show that ((cos theta - cos 3theta)(sin 8theta + sin 2 theta))/((sin 5 theta - sin theta)(cos 4 theta - cos 6 theta)) = 1

Prove that ((cos theta-cos 3 theta)(sin 8 theta +sin 2 theta))/((sin 5 theta-sin theta)(cos 4 theta-cos 6 theta))=1

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

(b)Show that (sin theta+sin 3theta+sin 5 theta+sin 7 theta)/(cos theta+cos3theta+cos 5 theta+cos 7 theta)=tan 4 theta .

Prove that :(sin5 theta+sin3 theta)/(cos5 theta+cos3 theta)=tan4 theta

If 32sin^(6)theta=10-15cos2 theta+b cos4 theta+a cos6 theta ,show that tan theta tan5 theta=(a+b-5)/(a-b+7)