" 5."(i)f(x)=(x^(2)-25)/(x+5)quad (NCERT)

Find the value of the constant k so that the given function is continuous at the indicated point: f(x)={(x^(2)-25)/(x-5),quad x!=5k,quad x=5 at x=5

Examine the following functions for continuity: (c) f(x) = (x^(2) - 25)/(x +5), x != -5

Examine the following functions for continuity. (a) f(x)=x-5 (b) f(x)=1/(x-5) (c) f(x)=(x^2-25)/(x+5) (d) f(x)=|x-5|

Examine the following functions for continuity. (a) f(x)=x-5 (b) f(x)=1/(x-5) (c) f(x)=(x^2-25)/(x+5) (d) f(x)=|x-5|

Examine the following functions for continuity.f(x)=x-5 (b) f(x)=(1)/(x-5) (c) f(x)=(x^(2)-25)/(x+5)f(x)=(x^(2)-25)/(x+5)

Examine the following functions for continuity. f(x)= (x^(2)-25)/(x+ 5), x ne -5

Simplify (x^(2)-5)(x+5)+25

If f(x)={((x^(2)-25)/(x-5)" , "xne5),(k" , "x=5):} is continuous at x=5, then k is equal to:

Examine the following functions for continuity f(x)=(x^(2)-25)/(x+5),x!=-5

Examine the following functions for continuity : f(x)=(x^(2)-25)/(x+5),xne-5