" (b) "(-3)/(5)" from "(7)/(25)

2 3/5-:5/7=\ (a) (13)/7 (b) (13)/(25) (c) (91)/(25) (d) (25)/(91)

2 3/5-:5/7=\ (13)/7 (b) (13)/(25) (91)/(25) (d) (25)/(91)

((-2)/5)^7-:((-2)/5)^5 is equal to (a) 4/(25) (b) (-4)/(25) (c) ((-2)/5)^(12) (d) (25)/4

((-2)/5)^7-:((-2)/5)^5 is equal to 4/(25) (b) (-4)/(25) (c) ((-2)/5)^(12) (d) (25)/4

" If "cos A=-(3)/(5),sin B=(7)/(25)" and "90^(@)

(2/3)^(-5)x\ (5/7)^(-5) is equal to (2/3x5/7)^(-10) (b) (2/3x5/7)^(-5) (c) (2/3x5/7)^(25) (d) (2/3x5/7)^(-25)

(2/3)^(-5)x\ (5/7)^(-5) is equal to (a) (2/3x5/7)^(-10) (b) (2/3x5/7)^(-5) (c) (2/3x5/7)^(25) (d) (2/3x5/7)^(-25)

If in a Delta ABC, two sides are a=3,b=5 and cos(A-B)=(7)/(25), find (tan)(c)/(2)

Subtract: (a b)/7-(35)/3b c+6/5ac from 3/5b c-4/5a c

Find the vector from the origin to the intersection of the medians of the triangle whose vertices are A(-1,-3),B(5,7) and C(2,5)