" 4) "5" sin "^(2)(2x+5)dx

int sin^(2)(2x+5)dx

int sin ^ (2) (2x + 5) dx

int "sin"^(5) x/2 dx

int_(0)^((pi)/(2))((cos x)/(6-5sin x+sin^(2)x))dx

int((sin2x+sin5x-sin3x)/(cos x+1-2sin^(2)2x))dx

int(5)/(sin^(2)x cos^(2)x)dx

(3) int sin^(5)((x)/(2))dx

int (sin ^ (2) x cos ^ (2) x) / ((sin ^ (5) x + cos ^ (3) x sin ^ (2) x + sin ^ (3) x cos ^ (2) x + cos ^ (5) x) ^ (2)) dx

int(sin2x+sin5x-sin3x)/(cos x+1-2sin^(2)2x)dx