" (v) "(3-2sqrt(2))/(3+2sqrt(2))

Rationalise the denominator of each of the following. (i) (1)/(sqrt(7)) (ii) (sqrt(5))/(2sqrt(3)) (iii) (1)/(2+ sqrt(3)) (1)/(sqrt(3)) (v) (1)/((5+3sqrt(2)) (vi) (1)/(sqrt(7) - sqrt(6)) (vi) (1)/(sqrt(7) - sqrt(6)) (viii) (1+ sqrt(2))/(2-sqrt(2)) (ix) (3-2sqrt(2))/(3+2sqrt(2))

Simplify : (5+sqrt(5))(5-sqrt(5)) (ii) (3+2sqrt(2))(3-2sqrt(2))

Simplify : (i) (5+sqrt(5))(5-sqrt(5)) (ii) (3+2sqrt(2))(3-2sqrt(2))

Simplify: (i) (5+\ sqrt(5))\ (5-\ sqrt(5)) (ii) (3+2sqrt(2))\ (3-2sqrt(2))

Simplify: (5+sqrt(5))(5-sqrt(5))( ii) (3+2sqrt(2))(3-2sqrt(2))

(1)/(sqrt(9)-sqrt(8)) is equal to: 3+2sqrt(2)(b)(1)/(3+2sqrt(2)) (c) 3-2sqrt(2)(d)(3)/(2)-sqrt(2)

1/(sqrt(9)-\ sqrt(8)) is equal to: (a) 3+2sqrt(2) (b) 1/(3+2sqrt(2)) (c) 3-2sqrt(2) (d) 3/2-\ sqrt(2)

The sum of two numbers is 6 times their geometric means, show that numbers are in the ratio (3+2sqrt(2)):(3-2sqrt(2)) .

The sum of two numbers is 6 xx their geometric means,show that numbers are in the ratio (3+2sqrt(2)):(3-2sqrt(2))