A magnet, whose poles are 10 cm apart is placed in the magnetic meridian. The intensity due to the magnet balances the earth's field `(3.6 xx 10^(-5)T)` at a point 9 cm from either pole. Find the pole strength of the magent.

A magnet whose poles are 12 cm apart is placed in the magnetic meridian. The field due to this magnet counterbalances the earth's horizontal field (H = 30 Am^(-1)) at a point 10 cm from each pole. Find the pole strength of the magnet.

A bar magnet 30 cm long is placed in the magnetic meridian with its north pole pointing geographical south . The neutral point is found at a distance of 30 cm from its centre . Calculate the pole strength of the magnet . Given B_(H) = 0.34 G .

A 30 cm long bar magnet is placed in the magnetic meridian with its north pole pointing south. The neutral point is obtained at a distance of 40 cm from the centre of the magnet. Pole strength of the magnet is (The horizontal component of earth’s magnetic field is 0.34 Gauss)

A bar magnet 30cm long is placed in magnetic meridian with its north pole pointing south. The neutral point is observed at a distance of 30cm from its centre. Calculate the pole strength of the magnet. Given horizontal component of earth's field is 0*34G .

A bar magnet of length 10cm is placed in the magnetic meridian with its north pole pointing towards the geographical north. A neutral point is obtained at a distance of 12cm from the centre of the magnet. Find the magnetic moment of the magnet, when H=0*34 gauss .

A bar magnet of length 14 cm is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of 18 cm from the center of the magnet. If B_(H)=0.4 G, the magnetic moment of the magnet is (1G = 10 ^(-4) T)

The moment of a magnet is 3 xx 10^(-1)A m^(2) and the length of the magnet is 10cm. The pole strength of the magnet is (in A.m)