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A magnet of length 0.1 m and pole streng...

A magnet of length 0.1 m and pole strength 0.1 Am is freely suspended in a horizontal uniform magnetic field of intensity `0.18 xx 10^(-4)T`. Find the torque tending to restore the magnet to its original position of rest when it is deflected by `30^(@)` from that position.

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The correct Answer is:
`9 xx 10^(-8)Nm`
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NN GHOSH-MAGNETIC FIELD AND POTENTIAL-EXERCISES
  1. A magnetic needle of magnetic moment 0.9 Am^(2) and pole strength 5Am ...

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  2. A magnet of length 0.1 m and pole strength 0.1 Am is freely suspended ...

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  3. A bar magnet lies in a magnetic field of intensity 0.5 xx 10^(-4) tes...

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  4. A magnet of length 0.2 m balances the earth's horizontal field at a po...

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  5. The intensities of magnetic field at two points on the axis of a bar m...

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  6. Two magnets of moments m and 2m are mounted to form a cross. The combi...

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  7. A short magnet is placed horizontally in the magnetic meridian with it...

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  8. The intensities of a magnetic field at two points on the axis of a bar...

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  9. A short bar magnet is placed horizontally in the magnetic meridian wi...

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  10. A neutral point is found on the prolongation of the axis of a bar magn...

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  11. A magnet whose poles are 12 cm apart is placed in the magnetic meridia...

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  12. A uniformly magnetized bar of brittle steel is broken into two pieces,...

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  13. Calculate the moment of a magnet, which when placed at right angles to...

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  14. A neutral point is found on the prolongation of the axis of a bar magn...

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  15. A bar magnet whose poles are 10 cm apart in the magnetic meridian with...

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  16. A long, vertical magnet is placed at a perpendicular distance of 0.8m ...

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  17. A magnet placed in the magnetic merdian with its north pole pointing n...

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  18. Two short magnets of the same type, but of moments m and 2m are mounte...

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  19. Assuming theta = pi//2 as the zero-energy position of a magnet in a ma...

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  20. Show that the force of attraction between two short magnets of moment ...

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