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Calculate the moment of a magnet, which ...

Calculate the moment of a magnet, which when placed at right angles to the horizontal magnetic field of the earth of intensity `30 Am^(-1)` experiences a couple of `3 xx 10^(-4)` newton metre.
[Hint: `B_(0) = mu_(0)H_(0) = 4pi xx 10^(-7) xx 30 `tesla and `tau = mB_(0) sin theta`]

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The correct Answer is:
`7.958 Am^(2)`
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NN GHOSH-MAGNETIC FIELD AND POTENTIAL-EXERCISES
  1. A bar magnet lies in a magnetic field of intensity 0.5 xx 10^(-4) tes...

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  2. A magnet of length 0.2 m balances the earth's horizontal field at a po...

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  3. The intensities of magnetic field at two points on the axis of a bar m...

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  4. Two magnets of moments m and 2m are mounted to form a cross. The combi...

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  5. A short magnet is placed horizontally in the magnetic meridian with it...

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  6. The intensities of a magnetic field at two points on the axis of a bar...

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  7. A short bar magnet is placed horizontally in the magnetic meridian wi...

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  8. A neutral point is found on the prolongation of the axis of a bar magn...

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  9. A magnet whose poles are 12 cm apart is placed in the magnetic meridia...

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  10. A uniformly magnetized bar of brittle steel is broken into two pieces,...

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  11. Calculate the moment of a magnet, which when placed at right angles to...

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  12. A neutral point is found on the prolongation of the axis of a bar magn...

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  13. A bar magnet whose poles are 10 cm apart in the magnetic meridian with...

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  14. A long, vertical magnet is placed at a perpendicular distance of 0.8m ...

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  15. A magnet placed in the magnetic merdian with its north pole pointing n...

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  16. Two short magnets of the same type, but of moments m and 2m are mounte...

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  17. Assuming theta = pi//2 as the zero-energy position of a magnet in a ma...

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  18. Show that the force of attraction between two short magnets of moment ...

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  19. A bar magnet of moment m = 4.0 Am^(2) lies on a table horizontally in ...

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  20. Find the force between two small circular coils of radii r(1) = 1 cm, ...

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