Home
Class 12
PHYSICS
The vertical component of the earth's fi...

The vertical component of the earth's field at a place is `40Am^(-1)` Calculate value of `H_(0)` , if dip of the place is `30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
`69.28Am^(-1)`
Promotional Banner

Topper's Solved these Questions

  • POTENTIOMETER

    NN GHOSH|Exercise EXERCISES|16 Videos

  • WHEATSTONE BRIDGE, METER BRIDGE

    NN GHOSH|Exercise Exercise|10 Videos

Similar Questions

Explore conceptually related problems

The vartical component of the earth's magnetic field is zero at a place where the angle of dip is

The horizontal component of the earth's magnetic field at any place is 0.36 xx 10^(-4) Wb m^(-2) If the angle of dip at that place is 60 ^@ then the value of the vertical component of earth's magnetic field will be ( in Wb m^(-2))

The vertical component of the earth’s magnetic field at a place is 0.24sqrt3xx10^-4 T Find out the value of horizontal component of the earth’s magnetic field, if angle of dip at that place is 30^@ .

The ratio of the vertical component to the horizontal component of earth's magnetic field at a place is 1 . What is the angle of dip at that place ?

The vertical component of earth's magnetic field at a place is sqrt3 times the horizontal component the value of angle of dip at this place is

The value of horizontal component of earth's magnetic field at a place is -.35xx10^(-4)T . If the angle of dip is 60^(@) , the value of vertical component of earth's magnetic field is about:

If horizontal and vertical components of the earths magnetic field are equal at a certain place, then the angle of dip at that place will be