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The force on a positively charged partic...

The force on a positively charged particle is given by `vecF=qvecE+qvecvxxvecB`.In a certain space there is a magnetic field B along y-axis and an electric field along x-axis.A positively charged particle is projected into this space.Find the direction and magnitude of minimum velocity so that it may pass on undeviated.

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The correct Answer is:
`v_("min")=E/B`, perpendicular to `vecE` and `vecB`
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