A simple pendulum of length `l` is suspended in a car that is travelling with a constant speed `v` around a circle of radius `r`. If the pendulum undergoes small oscillations about its equilibrium position , what will its freqeuency of oscillation be ?

Answer

`(1)/(2pi)sqrt((g)/(1)(1+(v^(4))/(r^(2)g^(2)))^((1)/(2)))`