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A 40-kg mass hanging at the end of a rop...

A 40-kg mass hanging at the end of a rope of length `l`. Oscillates in a vertical plane with an angular of `theta_(0)`. What is the tension in the rope when it makes an angle `theta` with the vertial ? If the breaking strength of the rope is 80 kg, what is the maximum angular amplitude with which the mass can oscillate without the rope breaking ?

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The correct Answer is:
`T = 392(3 cos theta - 2 cos theta_(0))N, theta_(0)=60^(@)`
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